LeetCode Q 240 - Search a 2D Matrix II
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
- Integers in each row are sorted in ascending from left to right.
- Integers in each column are sorted in ascending from top to bottom.
Solution
Begin our search at the top right corner of the matrix.
- If the target is large than this number, then we find numbers below it.
- If the target is small than this number, then we find numbers on the left of it.
Code:
public boolean searchMatrix(int[][] matrix, int target) {
if (matrix == null || matrix.length == 0 || matrix[0].length == 0)
return false;
int row = matrix.length, col = matrix[0].length;
int r = 0, c = col - 1;
while (r < row && c >= 0) {
if (matrix[r][c] == target)
return true;
else if (matrix[r][c] < target)
r++;
else
c--;
}
return false;
}