LeetCode Q 241 - Different Ways to Add Parentheses
Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *.
Example 1:Input: "2-1-1" ; Output: [0, 2]
Explanation:((2-1)-1) = 0 , (2-(1-1)) = 2
Example 2:Input: "2*3-4*5" ; Output: [-34, -14, -10, -10, 10]
Explanation:(2*(3-(4*5))) = -34 , ((2*3)-(4*5)) = -14 , ((2*(3-4))*5) = -10
(2*((3-4)*5)) = -10 , (((2*3)-4)*5) = 10
Solution : Divide and Conquer
Code:
public List<Integer> diffWaysToCompute(String input) {
List<Integer> res = new ArrayList<>();
if (input == null || input.length() == 0) return res;
for (int i = 0; i < input.length(); i++) {
if (input.charAt(i) == '+' || input.charAt(i) == '-' || input.charAt(i) == '*') {
List<Integer> left = diffWaysToCompute(input.substring(0, i));
List<Integer> right = diffWaysToCompute(input.substring(i + 1));
for (int num1: left) {
for (int num2: right) {
if (s.charAt(i) == '+') res.add(num1 + num2);
else if (s.charAt(i) == '-') res.add(num1 - num2);
else if (s.charAt(i) == '+') res.add(num1 * num2);
}
}
}
}
if (res.size() == 0)
res.add(Integer.parseInt(input));
return res;
}