LeetCode Q 108 - Convert Sorted Array to Binary Search Tree
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
Example: Given the sorted array: [-10,-3,0,5,9]
One possible answer is: [0,-3,9,-10,null,5]
Solution:
Code:
public TreeNode sortedArrayToBST(int[] nums) {
return dfs(nums, 0, nums.length - 1);
}
private TreeNode dfs(int[] nums, int left, int right) {
if (left > right) return null;
if (left == right) return new TreeNode(nums[left]);
int mid = left + (right - left) / 2;
TreeNode n = new TreeNode(nums[mid]);
n.left = dfs(nums, left, mid - 1);
n.right = dfs(nums, mid + 1, right);
return n;
}